Step 1 :The function $f(x)=|x|$ is already symmetric with respect to the y-axis. Therefore, reflecting it across the y-axis will not change the function. So, $g(x) = f(x) = |x|$.
Step 2 :This can be written in the form $a|x-h|+k$ as $1|x-0|+0$.
Step 3 :Final Answer: $g(x) = \boxed{1|x-0|+0}$