An object is moving in a circular path with a radius of $5.00 \mathrm{~m}$. If the object moves through an angle of 270 degrees, then the tangential distance traveled by the object is Multiple Choice $4.71 \mathrm{~m}$. $15.2 \mathrm{~m}$. $23.6 \mathrm{~m}$. $40.2 \mathrm{~m}$.

Step 1 ：Convert the angle from degrees to radians using the formula \(\theta = \frac{270}{180}\pi = 1.5\pi\) radians

Step 2 ：Substitute \(r = 5.00 m\) and \(\theta = 1.5\pi\) into the formula \(d = r * \theta\)

Step 3 ：Calculate the tangential distance as \(d = 5.00 m * 1.5\pi = 7.5\pi m\)

Step 4 ：Convert the result to a decimal by multiplying 7.5 by the value of \(\pi\) (approximately 3.14159), \(d = 7.5 * 3.14159 = 23.56 m\)

Step 5 ：\(\boxed{23.6 m}\) is the closest answer