Step 1 :Given the repair costs for a low-impact collision in a simple random sample of mini- and micro-vehicles, we have the following data: \$3130, \$1084, \$721, \$661, \$793, \$1755, \$3328, \$2007, \$2605, \$1350.
Step 2 :First, we calculate the mean of the data, which is \$1743.4.
Step 3 :Next, we calculate the standard deviation of the data, which is \$997.51.
Step 4 :The sample size, denoted as \(n\), is 10.
Step 5 :We then calculate the t-score for a 95% confidence interval, which is 2.262.
Step 6 :Using these values, we can calculate the lower and upper bounds of the confidence interval. The lower bound is calculated as \(mean - t\_score \times \frac{std\_dev}{\sqrt{n}}\), which gives us \$1029.82. The upper bound is calculated as \(mean + t\_score \times \frac{std\_dev}{\sqrt{n}}\), which gives us \$2456.98.
Step 7 :Rounding to the nearest dollar, we get the lower bound as \$1030 and the upper bound as \$2457.
Step 8 :\(\boxed{\text{Final Answer: We are 95% confident that the mean cost of repair is between \$1030 and \$2457.}}\)