Find the sum of the sequence. \[ \sum_{k=6}^{18} k^{3} \] \[ \sum_{k=6}^{18} k^{3}=\square \]

Step 1 ：We are asked to find the sum of the sequence \(\sum_{k=6}^{18} k^{3}\).

Step 2 ：We will use a for loop to iterate over the range from 6 to 18. For each iteration, we will cube the current number and add it to a running total.

Step 3 ：After the loop finishes, the total will be the sum of the cubes of the numbers from 6 to 18.

Step 4 ：The total sum of the cubes from 6 to 18 is 29016.

Step 5 ：So, the final answer is \(\sum_{k=6}^{18} k^{3}=\boxed{29016}\).