Find the determinant of the 3x3 matrix: \[A = \begin{bmatrix} 2 & 5 & -3 \ 1 & -2 & 2 \ 0 & 5 & -1 \end{bmatrix}\]

Step 1 ：Step 1: Use the formula for finding the determinant of a 3x3 matrix, which is: \[det(A) = a(ei−fh)−b(di−fg)+c(dh−eg)\] where a, b, c, d, e, f, g, h, and i are the elements of the matrix.

Step 2 ：Step 2: Substitute the matrix elements into the formula: \[det(A) = 2((-2)*(-1)−(2*5))−5((1)*(-1)−(2*0))+(-3)((1)*(5)−(-2*0))\]

Step 3 ：Step 3: Simplify the above expression: \[det(A) = 2*(2−10)−5*(-1)+(-3)*(5) = 2*(-8) + 5 +(-15) = -16 + 5 -15\]