Use the data in the following table, which lists drive-thru order accuracy at popular fast food chains. Assume that orders are randomly selected from those included in the table. Drive-thru Restaurant \begin{tabular}{|l|c|c|c|c|} \hline & A & B & C & D \\ \hline Order Accurate & 316 & 262 & 247 & 142 \\ \hline Order Not Accurate & 32 & 53 & 31 & 13 \\ \hline \end{tabular} If two orders are selected, find the probability that they are both from Restaurant D. Assume that the selections are made with replacement and do not round until the final answer; round to four decimal places. A. 0.0200 B. 0.0037 C. 0.0123 D. 0.0384 Moving to another question will save this response. Question 1 of 20

Step 1 ：First, calculate the total number of orders from all restaurants. This is done by adding the number of accurate and not accurate orders from all restaurants. In this case, the total number of orders is \(316 + 262 + 247 + 142 + 32 + 53 + 31 + 13 = 1096\).

Step 2 ：Next, calculate the total number of orders from Restaurant D. This is done by adding the number of accurate and not accurate orders from Restaurant D. In this case, the total number of orders from Restaurant D is \(142 + 13 = 155\).

Step 3 ：Then, calculate the probability of selecting an order from Restaurant D. This is done by dividing the total number of orders from Restaurant D by the total number of orders from all restaurants. In this case, the probability is \(\frac{155}{1096} = 0.14142335766423358\).

Step 4 ：Since the selections are made with replacement, the probability of selecting two orders from Restaurant D is the square of the probability of selecting one order from Restaurant D. In this case, the probability is \(0.14142335766423358^2 = 0.020000566093025737\).

Step 5 ：Finally, round the final answer to four decimal places. The final answer is \(\boxed{0.0200}\).