Step 1 :Define the problem as a linear programming problem with two variables: the number of Pomegranate computers (x) and the number of Izac computers (y).
Step 2 :The objective function to minimize is \(4000x + 4000y\) (since each computer costs $4000).
Step 3 :The constraints are: \(400x + 300y \geq 41000\) (for the memory) and \(80x + 100y \geq 11000\) (for the disk space).
Step 4 :We also have the constraints \(x \geq 0\) and \(y \geq 0\) since we can't buy a negative number of computers.
Step 5 :Solve the linear programming problem using a suitable method.
Step 6 :The solution shows that the school should buy 50 Pomegranate computers and 70 Izac computers to minimize the cost while satisfying the memory and disk space requirements.
Step 7 :Final Answer: The school should buy \(\boxed{50}\) Pomegranate computers and \(\boxed{70}\) Izac computers.