Problem

Find $y^{\prime}$ if $x^{y}=y^{x}$. \[ y^{\prime}= \]

Solution

Step 1 :\(\ln(x^{y}) = \ln(y^{x})\)

Step 2 :\(y\ln(x) = x\ln(y)\)

Step 3 :\(y'\ln(x) + \frac{y}{x} = \ln(y) + \frac{xy'}{y}\)

Step 4 :\(y'(\ln(x) - \frac{x}{y}) = \ln(y) - \frac{y}{x}\)

Step 5 :\(\boxed{y' = \frac{\ln(y) - \frac{y}{x}}{\ln(x) - \frac{x}{y}}}\)

From Solvely APP
Source: https://solvelyapp.com/problems/MTAQszBaWU/

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