Step 1 :The sample proportion, denoted as $\hat{p}$, is a random variable because its value varies from sample to sample. The source of this variability is the differing levels of satisfaction among individuals.
Step 2 :We can calculate the standard deviation of the sampling distribution using the formula $\sqrt{p(1-p)/n}$, where $p$ is the population proportion and $n$ is the sample size. In this case, $p = 0.74$ and $n = 100$.
Step 3 :The standard deviation of the sampling distribution, $\sigma_{\hat{p}}$, is approximately 0.044.
Step 4 :The model requirements for the sampling distribution of $\hat{p}$ are that the sample size is no more than 5% of the population size and that $np(1-p) \geq 10$. Since we don't know the population size, we can't check the first condition. However, the second condition is satisfied.
Step 5 :The sampling distribution of $\hat{p}$ is approximately normal because the sample size is large enough (n = 100) and the condition $np(1-p) \geq 10$ is satisfied. The mean of the distribution, $\mu_{\hat{p}}$, is equal to the population proportion, p = 0.74. The standard deviation of the distribution, $\sigma_{\hat{p}}$, is approximately 0.044.
Step 6 :Final Answer: The sample proportion $\hat{p}$ is a random variable because the value of $\hat{p}$ varies from sample to sample. The variability is due to the fact that different people feel differently regarding their satisfaction. The sampling distribution of $\hat{p}$ is approximately normal with $\mu_{\hat{p}} = 0.74$ and $\sigma_{\hat{p}} \approx 0.044$. The model requirements are satisfied because the sample size is large enough and $np(1-p) \geq 10$.