Step 1 :This is a binomial probability problem. The probability of success (ordering the chef's special) is 20% or 0.2. We want to find the probability of exactly 2 successes in 10 trials (customers).
Step 2 :The formula for binomial probability is: \(P(X=k) = C(n, k) * (p^k) * ((1-p)^(n-k))\), where: \(P(X=k)\) is the probability of k successes in n trials, \(C(n, k)\) is the combination of n items taken k at a time, p is the probability of success, n is the number of trials, and k is the number of successes.
Step 3 :We can plug in the values into the formula: n = 10, k = 2, p = 0.2, and calculate the result.
Step 4 :The combination of 10 items taken 2 at a time is 45.
Step 5 :The probability is calculated as \(P(X=2) = C(10, 2) * (0.2^2) * ((1-0.2)^(10-2)) = 0.302\).
Step 6 :Final Answer: The probability that 2 out of the next ten customers will order the chef's special is \(\boxed{0.302}\).