Question Solve the equation for all values of $\mathrm{x}$ by completing the square. \[ 3 x^{2}+90=36 x \] Answer Attempt 1 out of 2

Step 1 ：The given equation is a quadratic equation. To solve for x, we can rearrange the equation to the standard form of a quadratic equation, which is \(ax^2 + bx + c = 0\).

Step 2 ：Rearrange the given equation \(3x^2 + 90 = 36x\) to the standard form, we get \(3x^2 - 36x + 90 = 0\).

Step 3 ：Complete the square to solve for x, we get the solutions \(x = 6 - \sqrt{6}\) and \(x = 6 + \sqrt{6}\).

Step 4 ：The solutions to the equation are \(x = 6 - \sqrt{6}\) and \(x = 6 + \sqrt{6}\). These are the values of x that satisfy the given equation.

Step 5 ：Final Answer: The solutions to the equation are \(x = \boxed{6 - \sqrt{6}}\) and \(x = \boxed{6 + \sqrt{6}}\).