For each ordered pair, determine whether it is a sol \[ \left\{\begin{array}{l} 12 x+3 y=9 \\ y=-4 x+3 \end{array}\right. \] \begin{tabular}{|c|c|c|} \hline \multirow{2}{*}{$(x, y)$} & \multicolumn{2}{|c|}{ Is it a solution? } \\ \cline { 2 - 3 } & Yes & No \\ \hline$(0,-7)$ & 0 & 0 \\ \hline$(3,-9)$ & 0 & $\bigcirc$ \\ \hline$(-2,11)$ & 0 & 0 \\ \hline$(1,5)$ & 0 & 0 \\ \hline \end{tabular}

Step 1 ：Substitute x = 0 and y = -7 into the first equation: \(12(0) + 3(-7) = 9\)

Step 2 ：\(0 - 21 = 9\)

Step 3 ：\(-21 \neq 9\)

Step 4 ：Therefore, (0,-7) is not a solution to the system of equations.

Step 5 ：Substitute x = 3 and y = -9 into the first equation: \(12(3) + 3(-9) = 9\)

Step 6 ：\(36 - 27 = 9\)

Step 7 ：\(9 = 9\)

Step 8 ：Then substitute x = 3 and y = -9 into the second equation: \(-9 = -4(3) + 3\)

Step 9 ：\(-9 = -12 + 3\)

Step 10 ：\(-9 = -9\)

Step 11 ：Therefore, (3,-9) is a solution to the system of equations.

Step 12 ：Substitute x = -2 and y = 11 into the first equation: \(12(-2) + 3(11) = 9\)

Step 13 ：\(-24 + 33 = 9\)

Step 14 ：\(9 = 9\)

Step 15 ：Then substitute x = -2 and y = 11 into the second equation: \(11 = -4(-2) + 3\)

Step 16 ：\(11 = 8 + 3\)

Step 17 ：\(11 = 11\)

Step 18 ：Therefore, (-2,11) is a solution to the system of equations.

Step 19 ：Substitute x = 1 and y = 5 into the first equation: \(12(1) + 3(5) = 9\)

Step 20 ：\(12 + 15 = 9\)

Step 21 ：\(27 \neq 9\)

Step 22 ：Therefore, (1,5) is not a solution to the system of equations.

Step 23 ：So, the solutions to the system of equations are \(\boxed{(3,-9)}\) and \(\boxed{(-2,11)}\).