For $f(x)=7 x$ and $g(x)=-x$, find each of the following a. $(f+g)(-3)$ b. $(f-g)(-1)$ c. $(f \cdot g)(2)$ d. $\left(\frac{1}{g}\right)(2)$ a. $(f+g)(-3)=-18$ (Simplify your answer) b. $(f-g)(-1)=-8$ (Simplify your answer) c. $(1 \cdot g)(2)=-28$ (Simplify your answer) d. $\left(\frac{1}{g}\right)(2)=\square$ (Simplify your answer)

Step 1 ：\(f(-3) = 7*(-3) = -21\)

Step 2 ：\(g(-3) = -(-3) = 3\)

Step 3 ：\((f+g)(-3) = f(-3) + g(-3) = -21 + 3 = -18\)

Step 4 ：\(\boxed{-18}\)

Step 5 ：\(f(-1) = 7*(-1) = -7\)

Step 6 ：\(g(-1) = -(-1) = 1\)

Step 7 ：\((f-g)(-1) = f(-1) - g(-1) = -7 - 1 = -8\)

Step 8 ：\(\boxed{-8}\)

Step 9 ：\(f(2) = 7*2 = 14\)

Step 10 ：\(g(2) = -(2) = -2\)

Step 11 ：\((f \cdot g)(2) = f(2) \cdot g(2) = 14 * -2 = -28\)

Step 12 ：\(\boxed{-28}\)

Step 13 ：\(g(2) = -(2) = -2\)

Step 14 ：\(\left(\frac{1}{g}\right)(2) = \frac{1}{g(2)} = \frac{1}{-2} = -0.5\)

Step 15 ：\(\boxed{-0.5}\)