Step 1 :Given expression is \(a^3 - 27\)
Step 2 :This is a difference of cubes, which can be factored using the formula \(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\)
Step 3 :In this case, \(a = a\) and \(b = 3\)
Step 4 :Applying the formula, we get \(a^3 - 27 = a^3 - 3^3 = (a - 3)(a^2 + 3a + 9)\)
Step 5 :So, the completely factored form of \(a^3 - 27\) is \(\boxed{(a - 3)(a^2 + 3a + 9)}\)