Solve the problem involving probabilities with independent events. A single die is rolled twice. Find the probability of getting a 2 the first time and a 6 the second time. $\frac{1}{12}$ $\frac{1}{6}$ $\frac{1}{36}$ $\frac{1}{3}$

Step 1 ：The problem involves two independent events: rolling a 2 on the first roll and rolling a 6 on the second roll. The probability of each event can be calculated separately and then multiplied together to find the overall probability.

Step 2 ：The probability of rolling a 2 on a six-sided die is \(\frac{1}{6}\), and the probability of rolling a 6 is also \(\frac{1}{6}\).

Step 3 ：Therefore, the overall probability is \(\frac{1}{6} \times \frac{1}{6} = \frac{1}{36}\).

Step 4 ：Final Answer: The probability of rolling a 2 on the first roll and a 6 on the second roll is \(\boxed{\frac{1}{36}}\).