Given the linear function \(f(x) = 3x - 2\), in which quadrant of the Cartesian plane is the point \((4, f(4))\)?

Step 1 ：First, find the y-coordinate of the point by substituting \(x = 4\) into the function: \(f(4) = 3(4) - 2 = 10\)

Step 2 ：The point is \((4, 10)\)

Step 3 ：A point is in the first quadrant if both its x-coordinate and y-coordinate are positive, which is the case for \((4, 10)\)