ind all real zeros of the function. \[ g(x)=-2 x\left(x^{2}-9\right)\left(x^{2}+36\right) \] If there is more than one answer, separate them with commas. \[ \text { zero(s): } \square \]

Step 1 ：Define the function \(g(x) = -2x(x^2 - 9)(x^2 + 36)\)

Step 2 ：Solve the equation \(g(x) = 0\) to find the zeros of the function

Step 3 ：The solutions are \(x = -3, 0, 3, -6i, 6i\)

Step 4 ：Filter out the real solutions, which are \(x = -3, 0, 3\)

Step 5 ：Final Answer: The real zeros of the function are \(\boxed{-3, 0, 3}\)