Step 1 :We are given a normal distribution with mean \(\mu = 65.1\) and standard deviation \(\sigma = 4.93\). We are asked to find the data value corresponding to the z-score \(z = -0.36\).
Step 2 :The z-score is a measure of how many standard deviations an element is from the mean. The formula for the z-score is \(z = \frac{x - \mu}{\sigma}\), where \(x\) is the data value we are trying to find.
Step 3 :We can rearrange this formula to solve for \(x\): \(x = z \cdot \sigma + \mu\).
Step 4 :Substituting the given values into this formula, we get \(x = -0.36 \cdot 4.93 + 65.1\).
Step 5 :Calculating the above expression, we get \(x = 63.325199999999995\).
Step 6 :Rounding to the nearest tenth as needed, we get \(x = 63.3\).
Step 7 :Final Answer: The data value corresponding to \(z=-0.36\) is \(\boxed{63.3}\).