Problem

Find the interval notation of the solution set of the inequality \(2x^{2} - 5x + 2 > 0\), then convert it into inequality notation.

Solution

Step 1 :First, we must solve the inequality. We start by finding the roots of the quadratic equation \(2x^{2} - 5x + 2 = 0\).

Step 2 :This can be done using the quadratic formula \(x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\), where \(a = 2\), \(b = -5\), and \(c = 2\).

Step 3 :Substituting the values, we get \(x = \frac{5 \pm \sqrt{(-5)^{2}-4*2*2}}{2*2}\) which simplifies to \(x = \frac{5 \pm \sqrt{9}}{4}\). Therefore, the roots of the equation are \(x = 1\) and \(x = 2\).

Step 4 :Since we want to find when the equation is greater than 0, we test the intervals \(-\infty, 1\), \(1, 2\), and \(2, \infty\) to determine where the function is positive.

Step 5 :If we substitute any value less than 1 into the equation, we get a positive result. If we substitute any value between 1 and 2, we get a negative result. If we substitute any value greater than 2, we get a positive result.

Step 6 :Therefore, the interval notation for the solution is \((-\infty, 1) \cup (2, \infty)\).

Step 7 :To convert this into inequality notation, we can write it as \(x < 1\) or \(x > 2\).

From Solvely APP
Source: https://solvelyapp.com/problems/ITcQtPMmPR/

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