Find the interval notation of the solution set of the inequality \(2x^{2} - 5x + 2 > 0\), then convert it into inequality notation.

Step 1 ：First, we must solve the inequality. We start by finding the roots of the quadratic equation \(2x^{2} - 5x + 2 = 0\).

Step 2 ：This can be done using the quadratic formula \(x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\), where \(a = 2\), \(b = -5\), and \(c = 2\).

Step 3 ：Substituting the values, we get \(x = \frac{5 \pm \sqrt{(-5)^{2}-4*2*2}}{2*2}\) which simplifies to \(x = \frac{5 \pm \sqrt{9}}{4}\). Therefore, the roots of the equation are \(x = 1\) and \(x = 2\).

Step 4 ：Since we want to find when the equation is greater than 0, we test the intervals \(-\infty, 1\), \(1, 2\), and \(2, \infty\) to determine where the function is positive.

Step 5 ：If we substitute any value less than 1 into the equation, we get a positive result. If we substitute any value between 1 and 2, we get a negative result. If we substitute any value greater than 2, we get a positive result.

Step 6 ：Therefore, the interval notation for the solution is \((-\infty, 1) \cup (2, \infty)\).

Step 7 ：To convert this into inequality notation, we can write it as \(x < 1\) or \(x > 2\).