Part 2 of 3 Points: 0 of 1 Save Determine the point estimate of the population proportion, the margin of error for the following confidence interval, and the number of individuals in the sample with the specified characteristic, $x$, for the sample size provided. Lower bound $=0.096$, upper bound $=0.334, n=1000$ The point estimate of the population proportion is 0.215 . (Round to the nearest thousandth as needed.) The margin of error is $\square$. (Round to the nearest thousandth as needed.) an example Get more help - Clear all Check answer

Step 1 ：Given the lower bound of the confidence interval is 0.096 and the upper bound is 0.334, with a sample size of 1000.

Step 2 ：The point estimate of the population proportion is the midpoint of the confidence interval. It can be calculated as the average of the lower and upper bounds of the confidence interval.

Step 3 ：Using the formula \( \frac{lower\_bound + upper\_bound}{2} \), we get \( \frac{0.096 + 0.334}{2} = 0.215 \).

Step 4 ：The margin of error is the difference between the point estimate and either end of the confidence interval. It can be calculated as the absolute difference between the point estimate and the lower or upper bound of the confidence interval.

Step 5 ：Using the formula \( |point\_estimate - lower\_bound| \), we get \( |0.215 - 0.096| = 0.119 \).

Step 6 ：Final Answer: The point estimate of the population proportion is \( \boxed{0.215} \) and the margin of error is \( \boxed{0.119} \).