Step 1 :The problem is asking to solve the equation \(2^{x}=20\) by two methods. First, we need to fill in the table for the values of \(x\) from 4.1 to 4.4 and calculate the corresponding \(2^{x}\) values. Then, we need to solve the equation using logarithms.
Step 2 :Fill in the table with the calculated values of \(2^{x}\) for each given \(x\). The table values are approximately [17.148, 18.379, 19.698, 21.112] for \(x\) values of 4.1, 4.2, 4.3, and 4.4 respectively.
Step 3 :From the table, we can see that the value of \(2^{x}\) is getting closer to 20 as \(x\) increases from 4.1 to 4.4. However, none of the values in the table are exactly 20.
Step 4 :Next, solve the equation using logarithms. The equation \(2^{x}=20\) can be rewritten in logarithmic form as \(x = \log_{2}{20}\).
Step 5 :Calculate the value of \(x\) using the logarithm formula. The approximate value of \(x\) is 4.3219.
Step 6 :Final Answer: Using the table, \(x\) is approximately between 4.3 and 4.4. Using logarithms, \(x\) is approximately \(\boxed{4.3219}\).