Score: $1 / 2$ Penalty: $0.5 \mathrm{off}$ Question Watch Video Show Examples A bag contains 6 red marbles, 2 blue marbles and 7 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 1oooth, that both marbles drawn will be red? Answer Attempt 1out of 2

Step 1 ：The total number of marbles in the bag is calculated as \(6 (red) + 2 (blue) + 7 (green) = 15 (total marbles)\).

Step 2 ：The probability of drawing a red marble on the first draw is calculated as \(\frac{6 (red marbles)}{15 (total marbles)} = 0.4\).

Step 3 ：After drawing one red marble, there are now 5 red marbles left and a total of 14 marbles in the bag.

Step 4 ：The probability of drawing a red marble on the second draw is calculated as \(\frac{5 (red marbles)}{14 (total marbles)} = approximately 0.357\).

Step 5 ：The probability of both events happening (drawing a red marble on the first draw and drawing a red marble on the second draw) is found by multiplying the probabilities of each event.

Step 6 ：So, the probability of drawing two red marbles in a row is calculated as \(0.4 * 0.357 = approximately 0.143\).

Step 7 ：\(\boxed{0.143}\) is the final answer to the nearest thousandth.