Question 3, 7.2.15 HW Score: $0 \%, 0$ of 12 points Part 1 of 2 Points: 0 of 1 Save Find the P-value for the indicated hypothesis test with the given standardized test statistic, z. Decide whether to reject $\mathrm{H}_{0}$ for the given level of significance $\alpha$. Right-tailed test with test statistic $z=1.28$ and $\alpha=0.07$ P-value $=\square$ (Round to four decimal places as needed.)

Step 1 ：Given a right-tailed test with test statistic \(z=1.28\) and significance level \(\alpha=0.07\).

Step 2 ：The P-value is the probability that a random variable is more extreme than the observed results, assuming the null hypothesis is true.

Step 3 ：In a right-tailed test, the P-value is the area to the right of the test statistic on the standard normal distribution.

Step 4 ：We can find this value using the cumulative distribution function (CDF) of the standard normal distribution, which gives the probability that a random variable is less than or equal to a given value.

Step 5 ：Since we want the area to the right of the test statistic, we subtract the CDF value from 1.

Step 6 ：The calculated P-value is approximately 0.1003.

Step 7 ：We compare this P-value with the significance level \(\alpha=0.07\) to decide whether to reject the null hypothesis.

Step 8 ：If the P-value is less than or equal to \(\alpha\), we reject the null hypothesis. Otherwise, we do not reject the null hypothesis.

Step 9 ：The P-value is approximately 0.1003, which is greater than the significance level \(\alpha=0.07\). Therefore, we do not reject the null hypothesis.

Step 10 ：Final Answer: The P-value is \(\boxed{0.1003}\).