Matthew invests $\$ 600$ into an account with a $2.3 \%$ interest rate that is compounded quarterly. How much money will he have in this account if he keeps it for 10 years? Round your answer to the nearest dollar.

Step 1 ：Define the variables: the principal amount \(P = \$600\), the annual interest rate \(r = 2.3\% = 0.023\), the number of times interest is compounded per year \(n = 4\), and the time in years \(t = 10\).

Step 2 ：Calculate the future value using the compound interest formula: \(A = P \times (1 + \frac{r}{n})^{n \times t}\).

Step 3 ：Substitute the values into the formula: \(A = 600 \times (1 + \frac{0.023}{4})^{4 \times 10}\).

Step 4 ：Round the result to the nearest dollar to get the future value of the investment.

Step 5 ：The future value of the investment is \$755.

Step 6 ：Final Answer: Matthew will have \(\boxed{755}\) dollars in his account after 10 years.