Problem

iz Question 10 of 20 The table shows the number, expressed in millions, of citizens who moved in 2004, categorized by where they moved and whether they were an owner or a renter. Find the probability, expressed as a decimal rounded to the nearest hundredth, that a randomly selected citizen who moved in 2004 was an owner who moved to Number of People in a Certain Country Who Movec \begin{tabular}{|c|c|c|c|} \hline & \begin{tabular}{c} Moved to \\ Same \\ Region \end{tabular} & \begin{tabular}{c} Moved to \\ Different \\ Region \end{tabular} & \begin{tabular}{c} Moved to \\ Different \\ Country \end{tabular} \\ \hline Owner & 11.8 & 2.9 & 0.3 \\ \hline Renter & 18.6 & 4.4 & 1.0 \\ \hline \end{tabular} $\mathrm{P}$ (citizen was an owner who moved to a different country) $\approx 0.01$

Solution

Step 1 :The question is asking for the probability that a randomly selected citizen who moved in 2004 was an owner who moved to a different country. To find this, we need to divide the number of owners who moved to a different country by the total number of people who moved in 2004.

Step 2 :The number of owners who moved to a different country is given as 0.3 million. The total number of people who moved in 2004 can be found by adding up all the numbers in the table, which is 39.0 million.

Step 3 :Calculate the probability by dividing the number of owners who moved to a different country by the total number of people who moved. The calculation is \(\frac{0.3}{39.0}\).

Step 4 :The calculated probability is approximately 0.0077 when rounded to the nearest hundredth.

Step 5 :Final Answer: \(\boxed{0.01}\)

From Solvely APP
Source: https://solvelyapp.com/problems/Gndr9ugenj/

Get free Solvely APP to solve your own problems!

solvely Solvely
Download