Step 1 :First, divide the leading term of the dividend, \(10x^3\), by the leading term of the divisor, \(2x\), to get the first term of the quotient, \(5x^2\).
Step 2 :Next, multiply the divisor, \(2x + 4\), by the first term of the quotient, \(5x^2\), to get \(10x^3 + 20x^2\).
Step 3 :Subtract this from the original dividend, \(10x^3 + 14x^2 - 18x - 12\), to get a new dividend of \(-6x^2 - 18x - 12\).
Step 4 :Repeat the process: divide the leading term of the new dividend, \(-6x^2\), by the leading term of the divisor, \(2x\), to get the next term of the quotient, \(-3x\).
Step 5 :Then, multiply the divisor, \(2x + 4\), by the new term of the quotient, \(-3x\), to get \(-6x^2 - 12x\).
Step 6 :Subtract this from the new dividend, \(-6x^2 - 18x - 12\), to get a new dividend of \(-6x - 12\).
Step 7 :Repeat the process one more time: divide the leading term of the new dividend, \(-6x\), by the leading term of the divisor, \(2x\), to get the final term of the quotient, \(3\).
Step 8 :Then, multiply the divisor, \(2x + 4\), by the final term of the quotient, \(3\), to get \(6x + 12\).
Step 9 :Subtract this from the new dividend, \(-6x - 12\), to get a remainder of \(0\).
Step 10 :So, the quotient is \(5x^2 - 3x + 3\) and the remainder is \(0\).
Step 11 :Final Answer: \(\boxed{5x^2 - 3x + 3, 0}\)