Find the derivative of the function. \[ y=(5 t-1)(2 t-4)^{-1} \]

Step 1 ：Let's denote \(u = 5t - 1\) and \(v = (2t - 4)^{-1}\).

Step 2 ：Then, we have \(u' = 5\) and \(v' = -1 * (2t - 4)^{-2} * 2\) (using the chain rule), which simplifies to \(v' = -2/(2t - 4)^2\).

Step 3 ：Now, we can apply the product rule: \(y' = u'v + uv' = 5 * (2t - 4)^{-1} + (5t - 1) * -2/(2t - 4)^2\).

Step 4 ：Simplifying this gives: \(y' = 5/(2t - 4) - 2(5t - 1)/(2t - 4)^2\).

Step 5 ：So, the derivative of the function is \(\boxed{y' = 5/(2t - 4) - 2(5t - 1)/(2t - 4)^2}\).