Given $f(w)=-w^{3}+13$, find the following: a) $w$-intercept(s) $=$ b) $f(w)$-intercept $=$

Step 1 ：Set the function $f(w)$ equal to zero and solve for $w$ to find the $w$-intercept(s). So, $-w^{3}+13=0$.

Step 2 ：Rearrange the equation to get $w^{3}=13$.

Step 3 ：Take the cube root of both sides to find $w=\sqrt[3]{13}$. So, the $w$-intercept is $\boxed{\sqrt[3]{13}}$.

Step 4 ：Substitute $w=0$ into the function to find the $f(w)$-intercept. So, $f(0)=-0^{3}+13=13$. Therefore, the $f(w)$-intercept is $\boxed{13}$.