Step 1 :The function \(g(x)=2^{x}-1\) is a transformation of the function \(f(x)=2^{x}\).
Step 2 :The transformation is a vertical shift of the graph of \(f(x)\) 1 unit downward.
Step 3 :This is because the "-1" in the function \(g(x)\) subtracts 1 from each output value of the function \(f(x)\), which corresponds to moving the graph of \(f(x)\) down by 1 unit.
Step 4 :So, the correct answer is: \(\boxed{\text{A. The graph of } f(x)=2^{x} \text{ should be shifted 1 unit downward.}}\)
Step 5 :The domain of the function \(g(x)\) is the same as the domain of \(f(x)\), which is all real numbers.
Step 6 :The range of \(g(x)\) is all real numbers less than -1, because the graph of \(f(x)\) is always above the x-axis, and shifting it down by 1 unit makes the graph of \(g(x)\) always above the line y=-1.
Step 7 :The equation of the asymptote is y=-1, because that is the horizontal line that the graph of \(g(x)\) approaches as x goes to negative infinity.
Step 8 :You can confirm these results by graphing the functions \(f(x)\) and \(g(x)\) on a graphing utility. The graph of \(f(x)\) is a curve that starts near the x-axis for negative x and increases rapidly for positive x. The graph of \(g(x)\) is the same curve, but shifted down by 1 unit.