Step 1 :Step 1: Find the domain of each function separately.
Step 2 :For \(f(x) = \sqrt{x+2}\), the domain is \(x \geq -2\) because the expression under the square root must be greater than or equal to 0.
Step 3 :For \(g(x) = \frac{1}{x-3}\), the domain is \(x \neq 3\) because the denominator of a fraction cannot be 0.
Step 4 :Step 2: Combine the two domains.
Step 5 :The combined domain is the intersection of the two separate domains, which is \(x \geq -2\) and \(x \neq 3\).