Problem
Is there a doctor in the house? A market research firm reported the mean annual earnings of all family practitioners in the United States was $\$ 178,258$. A random sample of 54 family practitioners in Los Angeles had mean earnings of $\bar{x}=\$ 192,780$ with a standard deviation of $\$ 43,337$. Do the data provide sufficient evidence to conclude that the mean salary for family practitioners in Los Angeles differs from the national average? Use the $\alpha=0.05$ level of significance and the $P$-value method with the TI-84 Plus calculator. Part: 0 / 5 Part 1 of 5 (a) State the appropriate null and alternate hypotheses. \[ \begin{array}{l} H_{0}: \\ H_{1}: \end{array} \] This hypothesis test is a (Choose one) $\nabla$ test.
Solution
Step 1 ：State the null hypothesis (H0): \(\mu = 178258\), which means the mean salary for family practitioners in Los Angeles is equal to the national average.
Step 2 ：State the alternate hypothesis (H1): \(\mu \neq 178258\), which means the mean salary for family practitioners in Los Angeles is not equal to the national average.
Step 3 ：Identify that this hypothesis test is a two-tailed test.
