Step 1 :Given values are sample mean (\(x_{bar}\)) = 2.86, standard deviation (\(\sigma\)) = 0.78, sample size (n) = 15, and Z-score for 90% confidence interval (Z) = 1.645.
Step 2 :Calculate the margin of error using the formula: Margin of Error = Z * \(\sigma/\sqrt{n}\).
Step 3 :Substitute the given values into the formula: Margin of Error = 1.645 * (0.78/\(\sqrt{15}\)) = 0.3312949954345824.
Step 4 :Calculate the confidence interval using the formula: Confidence Interval = \(x_{bar}\) ± Margin of Error.
Step 5 :Substitute the values into the formula: Lower Limit = 2.86 - 0.3312949954345824 = 2.53 (rounded to the nearest hundredth), Upper Limit = 2.86 + 0.3312949954345824 = 3.19 (rounded to the nearest hundredth).
Step 6 :Final Answer: The 90% confidence interval for the population mean is \(\boxed{(2.53, 3.19)}\).