Solve for $x$. \[ 16^{6 x}=11^{-x-3} \] Write the exact answer using either base-10 or base- $e$ logarithms. \[ x=\square \] $\square \log \square$ $\square \ln \square$ No solution $x$ 5

Step 1 ：The given equation is in the form of \(a^{bx} = c^{dx}\), which can be solved by taking the logarithm on both sides. This will allow us to bring down the exponents and solve for \(x\).

Step 2 ：Taking the logarithm of both sides of the equation \(16^{6x} = 11^{-x - 3}\) gives us the equation \(x = -\frac{3 \log 11}{\log 184549376}\).

Step 3 ：\(\boxed{x = -\frac{3 \log 11}{\log 184549376}}\) is the solution to the equation.