Step 1 :The problem provides the measures of angles P, R, S, and T in terms of variables m and n. Specifically, we have \(\angle P = n^2 - 7^\circ\), \(\angle R = 54^\circ\), \(\angle S = 33^\circ\), and \(\angle T = 33^\circ\).
Step 2 :Since the sum of the angles in a triangle is \(180^\circ\), we can set up two equations to solve for m and n. The first equation will be \(m + 54 + 33 = 180\) and the second equation will be \(n^2 - 7 + 33 + 33 = 180\).
Step 3 :Solving the first equation gives \(m = 180 - 54 - 33 = 93\).
Step 4 :Solving the second equation gives \(n^2 = 180 - 59 = 121\). Taking the square root of both sides gives \(n = 11\) or \(n = -11\).
Step 5 :However, since the measure of an angle cannot be negative, we discard \(n = -11\). Therefore, the values of m and n are \(93^\circ\) and \(11^\circ\) respectively.
Step 6 :Final Answer: \(m = \boxed{93}\) and \(n = \boxed{11}\).