Problem
Giving a test to a group of students, the grades and gender are summarized below \begin{tabular}{|r|r|r|r|r|} \hline & A & B & C & Total \\ \hline Male & 14 & 13 & 3 & 30 \\ \hline Female & 20 & 8 & 10 & 38 \\ \hline Total & 34 & 21 & 13 & 68 \\ \hline \end{tabular} If one student is chosen at random, Find the probability that the student got a B: Find the probability that the student was female AND got a " $\mathrm{C}$ ": Find the probability that the student was male OR got an "A": If one student is chosen at random, find the probability that the student got a 'C' GIVEN they are male: Submit Question Type here to search
Solution
Step 1 ：Given that the total number of students is 68 and the number of students who got a B is 21.
Step 2 ：The probability of a student getting a B is calculated by dividing the number of students who got a B by the total number of students.
Step 3 ：Substituting the given values, we get \(\frac{21}{68} = 0.3088235294117647\).
Step 4 ：Rounding off to four decimal places, we get 0.3088.
Step 5 ：\(\boxed{0.3088}\) is the final answer.
