The function below has at least one rational zero. Use this fact to find all zeros of the function. \[ f(x)=7 x^{4}+36 x^{3}+48 x^{2}+11 x+6 \] If there is more than one zero, separate them with commas. Write exact values, not decimal approximations. \begin{tabular}{|l|l|} \hline$\square$ \\ \end{tabular}

Step 1 ：The Rational Root Theorem states that if a polynomial has a rational root, then it must be a factor of the constant term divided by a factor of the leading coefficient. In this case, the constant term is 6 and the leading coefficient is 7. So, the possible rational roots are factors of \(\frac{6}{7}\), which are ±1, ±2, ±3, ±6, ±\(\frac{1}{7}\), ±\(\frac{2}{7}\), ±\(\frac{3}{7}\), ±\(\frac{6}{7}\). We can use synthetic division to test these possible roots. If the remainder is 0, then we have found a root. Once we find a root, we can use it to factor the polynomial and find the remaining roots.

Step 2 ：The rational roots of the function are -2 and -3. Now, we can use these roots to factor the polynomial and find the remaining roots.

Step 3 ：The remaining roots of the function are complex numbers, specifically \(-\frac{1}{14} - \frac{3\sqrt{3}i}{14}\) and \(-\frac{1}{14} + \frac{3\sqrt{3}i}{14}\). Therefore, the function has four roots in total: -2, -3, \(-\frac{1}{14} - \frac{3\sqrt{3}i}{14}\), and \(-\frac{1}{14} + \frac{3\sqrt{3}i}{14}\).

Step 4 ：Final Answer: The zeros of the function are \(\boxed{-2, -3, -\frac{1}{14} - \frac{3\sqrt{3}i}{14}, -\frac{1}{14} + \frac{3\sqrt{3}i}{14}}\).