Step 1 :The function \(f(x)=2^{x}-3\) is a transformation of the function \(y=2^{x}\). Specifically, it is a vertical shift of the graph of \(y=2^{x}\) downwards by 3 units. This means that the y-coordinate of each point on the graph of \(y=2^{x}\) will be decreased by 3 to get the corresponding point on the graph of \(f(x)=2^{x}-3\).
Step 2 :To find the corresponding points that lie on the graph of \(f(x)=2^{x}-3\), we can subtract 3 from the y-coordinate of each point on the graph of \(y=2^{x}\).
Step 3 :The domain of the function \(f(x)=2^{x}-3\) is the same as the domain of the function \(y=2^{x}\), which is all real numbers. The range of the function \(f(x)=2^{x}-3\) is all real numbers less than -3, because the graph of \(y=2^{x}\) is always above the x-axis, and shifting it downwards by 3 units will make it always below the line \(y=-3\).
Step 4 :The y-intercept of the function \(f(x)=2^{x}-3\) is the y-coordinate of the point where the graph intersects the y-axis. This occurs when \(x=0\), so we can substitute \(x=0\) into the function to find the y-intercept.
Step 5 :The horizontal asymptote of the function \(f(x)=2^{x}-3\) is the line \(y=-3\), because the graph approaches this line as \(x\) goes to negative infinity.
Step 6 :The corresponding points that lie on the graph of \(f(x)=2^{x}-3\) are \(\boxed{(-1, -2.5)}\), \(\boxed{(0, -2)}\), and \(\boxed{(1, -1)}\). The y-intercept of the function is \(\boxed{-2}\).
Step 7 :The domain of the function is all real numbers, and the range is all real numbers less than -3. The equation of the horizontal asymptote is \(y=\boxed{-3}\).