Problem

Factor completely. Be sure to factor out the GCF when necessary. Select "Prime" if the polynomial cannot be factored. \[ x^{2}+2 x y-8 y^{2} \] \[ x^{2}+2 x y-8 y^{2}=\square \] Prime

Solution

Step 1 :The given expression is a quadratic expression in the form of \(ax^2 + bx + c\). To factorize it, we need to find two numbers such that their sum is equal to the coefficient of the middle term (which is 2 in this case) and their product is equal to the product of the coefficients of the first and last terms (which is -8 in this case).

Step 2 :By inspection, we can see that the two numbers that satisfy these conditions are -2 and 4. Therefore, we can write the given expression as \((x - 2y)(x + 4y)\).

Step 3 :\(\boxed{x^{2}+2 x y-8 y^{2}=(x - 2y)(x + 4y)}\)

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Source: https://solvelyapp.com/problems/DbQdOFZAKD/

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