Let $C=\left[\begin{array}{r}1 \\ -3 \\ 2\end{array}\right]$ and $D=\left[\begin{array}{r}-1 \\ 3 \\ -2\end{array}\right]$. Find $C-4 D$

Step 1 ：Let $C=\left[\begin{array}{r}1 \ -3 \ 2\end{array}\right]$ and $D=\left[\begin{array}{r}-1 \ 3 \ -2\end{array}\right]$. We are asked to find $C-4 D$.

Step 2 ：This operation involves subtracting 4 times the vector D from the vector C. Each component of the vectors will be operated separately. For instance, the first component of the result will be the first component of C minus 4 times the first component of D. The same applies for the second and third components.

Step 3 ：Performing the operation, we get the vector [5, -15, 10]. This is the result of the operation $C-4D$.

Step 4 ：Final Answer: $\boxed{\left[\begin{array}{r}5 \ -15 \ 10\end{array}\right]}$