Problem
2 in ane taber: Clay's Typing Rate \begin{tabular}{|c|c|} \hline \begin{tabular}{c} Time \\ (minutes) \end{tabular} & \begin{tabular}{c} Number of \\ Words Trped \end{tabular} \\ \hline 3 & 54 \\ \hline 5 & 90 \\ \hline 7 & 126 \\ \hline \end{tabular} Use points (0,0) and $(5,80)$ to find Marsha's rate Based on this information, which statement is true? A. Clay bypes at a rate of 16 words per minute: which is faster than Marsha. 1. Marsha tyoes at a rate of 16 wards per minute. which is faster than Clay- C. Clay types 2 more words per minute than Marsha. Q. Marsha types 2 more words per minute than Clay.
Solution
Step 1 ：\( \text{Words per minute} = \frac{\text{Total words}}{\text{Total minutes}} \)
Step 2 ：\( \text{Words per minute} = \frac{90}{5} \)
Step 3 ：\( \text{Words per minute} = 18 \)
Step 4 ：So, Marsha types at a rate of 18 words per minute.
Step 5 ：Now, let's find Clay's typing rate using the points (3,54).
Step 6 ：\( \text{Words per minute} = \frac{54}{3} \)
Step 7 ：\( \text{Words per minute} = 18 \)
Step 8 ：So, Clay also types at a rate of 18 words per minute.
Step 9 ：\(\boxed{\text{Therefore, Marsha and Clay type at the same rate, so none of the given options is correct.}}\)
