Step 1 :The question is asking about the end behavior of the function \(f(x)=2^{-x}+1\) as \(x\) goes to infinity. The end behavior of a function refers to the behavior of the function as the input values approach positive or negative infinity.
Step 2 :In this case, as \(x\) goes to infinity, \(2^{-x}\) goes to 0 because any positive number raised to the power of negative infinity is 0. Therefore, \(f(x)\) goes to \(0+1=1\).
Step 3 :The plot shows that as x goes to infinity, the function \(f(x)=2^{-x}+1\) approaches 1. This confirms my initial thought.
Step 4 :Final Answer: As \(x\) goes to infinity, \(f(x)\) goes to \(\boxed{1}\).