When point $F($ is reflected in the line $y=-x$, the image is located at $F^{\prime}(-7,1)$.

Step 1 ：When point $F$ is reflected in the line $y=-x$, the image is located at $F^{\prime}(-7,1)$.

Step 2 ：The reflection of a point across the line $y=-x$ results in a new point where the x and y coordinates are swapped and their signs are reversed.

Step 3 ：So, if the reflected point $F'$ is $(-7,1)$, then the original point $F$ should be $(1,7)$.

Step 4 ：Therefore, the original point $F$ before reflection was indeed $(1,7)$.

Step 5 ：Final Answer: The original point $F$ before reflection was $\boxed{(1,7)}$.