Step 1 :Define the number of trials as \(n = 10\)
Step 2 :Define the probability of success as \(p = 0.608\)
Step 3 :Calculate the cumulative distribution function for 3 or fewer successes, which is \(prob\_3\_or\_fewer = 0.049050811560599025\)
Step 4 :Calculate the probability of more than 3 successes, which is \(prob\_more\_than\_3 = 1 - prob\_3\_or\_fewer\)
Step 5 :Round the probability of more than 3 successes to 3 decimal places, which is \(prob\_more\_than\_3 = 0.951\)
Step 6 :Final Answer: The probability that more than 3 of the tickets have popcorn coupons is \(\boxed{0.951}\)