Step 1 :First, we factor both the numerator and the denominator. The numerator factors into \((3x-1)(x+2)\) and the denominator factors into \((x-2)(x+2)\).
Step 2 :Substituting the factored forms back into the expression, we get \(\frac{(3x-1)(x+2)}{(x-2)(x+2)}\).
Step 3 :We then cancel out the common factor \((x+2)\) from the numerator and the denominator, which leaves us with \(\frac{3x-1}{x-2}\).