Step 1 :The problem is asking for a test statistic to determine whether the proportion of female physics majors at a specific college differs significantly from the national average. The test statistic in this case would be a z-score, which measures how many standard deviations an element is from the mean.
Step 2 :To calculate the z-score, we need to use the formula: \(z = \frac{(p - P)}{\sqrt{(P * (1 - P)) / n}}\) where: p is the sample proportion (number of successes in the sample divided by the sample size), P is the population proportion (national average), and n is the sample size.
Step 3 :In this case, the sample proportion p is calculated as the number of successes in the sample divided by the sample size, which is \(p = \frac{11}{50} = 0.22\).
Step 4 :The population proportion P is the national average, which is \(P = 0.19\).
Step 5 :The sample size n is 50.
Step 6 :Substituting these values into the formula, we get \(z = \frac{(0.22 - 0.19)}{\sqrt{(0.19 * (1 - 0.19)) / 50}} = 0.54\).
Step 7 :The calculated z-score is approximately 0.54. This means that the proportion of female physics majors at the college is approximately 0.54 standard deviations above the national average.
Step 8 :Final Answer: The appropriate test statistic is approximately \(\boxed{0.54}\).