QUESTION 6 Solve the equation. \[ v(15 v-11)=-2 \] a) $v=\frac{2}{5} ; v=\frac{1}{3}$ b) $v=0 ; v=\frac{11}{15}$ c) $v=-\frac{2}{5} ; v=-\frac{1}{3}$ d) $v=\frac{2}{5} ; v=-\frac{1}{3}$ a.. b.. c.. d.. QUESTION 7

Step 1 ：Expand the equation: \(15v^2 - 11v = -2\)

Step 2 ：Rearrange the equation: \(15v^2 - 11v + 2 = 0\)

Step 3 ：Factor the quadratic equation: \((3v-2)(5v-1) = 0\)

Step 4 ：Set each factor equal to zero: \(3v-2 = 0\) or \(5v-1 = 0\)

Step 5 ：Solve for \(v\) in each equation: \(v = \frac{2}{3}\) or \(v = \frac{1}{5}\)

Step 6 ：Therefore, the correct answer is \(v = \frac{2}{3}\) or \(v = \frac{1}{5}\)