Suppose $\int_{2}^{4} f(x) d x=-5, \int_{2}^{7} f(x) d x=-4$, and $\int_{2}^{7} g(x) d x=2$. Evaluate the following integrals. \[ \int_{7}^{2} g(x) d x= \] (Simplify your answer.)

Step 1 ：Suppose we have the integral of a function g(x) from 2 to 7, denoted as \(\int_{2}^{7} g(x) d x=2\).

Step 2 ：The integral of a function from a to b is the negative of the integral from b to a. This is a property of definite integrals.

Step 3 ：Therefore, the integral of g(x) from 7 to 2 is the negative of the integral of g(x) from 2 to 7.

Step 4 ：Substituting the given value, we get \(\int_{7}^{2} g(x) d x = -2\).

Step 5 ：Final Answer: The value of the integral \(\int_{7}^{2} g(x) d x\) is \(\boxed{-2}\).