Problem

(Types of Area MC) A cone has a slant height of 8 inches and a diameter of 10 inches. What is the surface area of the cone? 65 in $^{2}$ $65 \pi$ in $^{2}$ $180 \mathrm{in}^{2}$ $180 \pi$ in $^{2}$

Solution

Step 1 :Given that the diameter of the cone is 10 inches, we can find the radius r which is half of the diameter. So, \(r = \frac{10}{2} = 5\) inches.

Step 2 :The slant height l is given as 8 inches.

Step 3 :The surface area A of a cone is given by the formula \(A = \pi r(r + l)\).

Step 4 :Substitute the values of r and l into the formula: \(A = \pi * 5 * (5 + 8)\).

Step 5 :Simplify the expression to find the surface area: \(A = \pi * 5 * 13 = 65\pi\) square inches.

Step 6 :\(\boxed{A = 65\pi}\) square inches is the surface area of the cone.

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Source: https://solvelyapp.com/problems/9WcusdJm9T/

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