Problem

Find the intersection of the solution sets of the following linear equations: \(2x - 3y = 6\) and \(5x + 4y = 20\).

Solution

Step 1 :First, solve each equation for y: \(y = \frac{2x - 6}{3}\) and \(y = \frac{20 - 5x}{4}\).

Step 2 :Then, set the two expressions for y equal to each other to find the x-value of the intersection: \(\frac{2x - 6}{3} = \frac{20 - 5x}{4}\). Solving this equation gives \(x = 2\).

Step 3 :Substitute \(x = 2\) into each of the original equations to find the corresponding y-values. For \(2x - 3y = 6\), this gives \(y = 0\), and for \(5x + 4y = 20\), this gives \(y = 0\) as well.

From Solvely APP
Source: https://solvelyapp.com/problems/9NJ8cEVqoe/

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