Question 11, IR.5.20 Check here for instructional material to complete this problem. Evaluate ${ }_{n} C_{x} p^{x}(1-p)^{n-x}$ for $n=6, p=0.2, x=2$ The answer is $\square$. (Round to four decimal places as needed.)

Step 1 ：Given that \(n = 6\), \(p = 0.2\), and \(x = 2\)

Step 2 ：First, calculate the binomial coefficient, which is \(_{n}C_{x}\). In this case, it is \(_{6}C_{2}\) which equals 15

Step 3 ：Next, calculate \(p^{x}\), which is \(0.2^{2}\) and equals 0.04

Step 4 ：Then, calculate \((1-p)^{n-x}\), which is \((1-0.2)^{6-2}\) and equals 0.4096

Step 5 ：Finally, multiply the binomial coefficient, \(p^{x}\), and \((1-p)^{n-x}\) together. So, \(15 \times 0.04 \times 0.4096 = 0.24576\)

Step 6 ：Round the result to four decimal places, the final answer is \(\boxed{0.2458}\)